The principle value of the amplitude of (1 + i) is

$\frac{π}{4}$

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$\frac{π}{12}$

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$\frac{3 π}{4}$

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$π$

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Solution

The correct option is A
$\frac{π}{4}$

Let z = (1 + i)

$t a n α = ∣ ∣ \frac{I m (z)}{R e (z)} ∣ ∣ = 1 \Rightarrow α = \frac{π}{4}$

Since, z lies in the first qudrant,

Therefore, arg (z) = $\frac{π}{4}$

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