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Question

The probabilities of different faces of a biased dice to appear are as follows
Face number123456Probability0.10.320.210.150.050.17
The dice is thrown and it is known that either the face number 1 or 2 will appear.  Then, the probability of the face number 1 to appear is
  1. 521
  2. 513
  3. 723
  4. 310


Solution

The correct option is A 521
The probability of the face number 1 to appear
=P(1)P(1)+P(2)=0.10.1+0.32=0.10.42=1042=521

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