Question

The probabilities of these mutually exclusive events A, B and C are given by $\frac{2}{3},\frac{1}{4}$ and $\frac{1}{6}$ resoectively. The statement

• A. is true
• B. is false
• C. nothing can be said
• D. could be either

Answer 1

The correct option is B

is false

Since the events A, B and C are mutually exclusive, we have :

$P(A\cup B\cup C)=\frac{2}{3}+\frac{1}{4}+\frac{1}{6}=\frac{13}{12}>1$

which is not possible.

Hence, the given statement is false.