Question

The probabilities of three mutually exclusive events A, B and C are given by 2/3, 1/4 and 1/6 respectively. The statement
(a) is true
(b) is false
(c) nothing can be said
(d) could be either

Answer 1

(b) is false

Since the events A, B and C are mutually exclusive, we have:
$P\left(A\cup B\cup C\right)=\frac{2}{3}+\frac{1}{4}+\frac{1}{6}=\frac{13}{12}>1$ , which is not possible.
Hence, the given statement is false.