Question

The probabilities of three mutually exclusive events A, B, C are given by $\frac{2}{3},\frac{1}{4},and\frac{1}{6}$ respectively. This statement

• A. Is true
• B. is false
• C. nothing can be said
• D. could be either

Answer 1

The correct option is B is false

Since the events A,B,C are mutually exclusive, we have
$P(A\bigcup B\bigcup C)=\frac{2}{3}+\frac{1}{4}+\frac{1}{6}=\frac{13}{12}>0$
Which is not possible , hence the statement is false.