The probabilities of three mutually exclusive events are 2/3, 1/4 and 1/6. The statement is [MNR 1987; UPSEAT

True

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Wrong

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Could be either

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Do not know

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Solution

The correct option is B
Wrong

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Similar questions

\frac{2}{3}, \frac{1}{4}, a n d \frac{1}{6}

The probabilities of these mutually exclusive events A, B and C are given by $\frac{2}{3}, \frac{1}{4}$ and $\frac{1}{6}$ resoectively. The statement

\frac{1 + 3 P}{3}, \frac{1 - P}{4}

\frac{1 - 2 P}{2}

P \in

\frac{1 + 3 p}{3}, \frac{1 - p}{4}

\frac{1 - 2 p}{2}

p \in

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