MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Quantitative Aptitude

Probability

The Probabili...

Question

The Probability Density Function (PDF) of two functions are given below:

If X and Y are independent random variable then of E[4X +3Y] is ___________
0

Open in App

Solution

The correct option is A 0
0
Since the PDFs are sysmmetrical about y - axis
E[X] = E[Y] = 0
4E[X] + 3E[Y] = 0

Suggest Corrections

thumbs-up

0

Similar questions

Q. The probability density functions of two independent random variables X and Y are given by,
Where a, b are positive real constants and u(•) represents the unit step function. The probability density functibn of the random variable Z = X + Y will be

f_{x} (x) = a e^{- a x} u (x) a n d f_{y} (y) = b e^{- b y} u (y)

Q. Two random variables

X

Y

have marginal probability density functions (PDFs)

f_{X} (x)

f_{Y} (y)

respectively, and they have a joint PDF of

f_{X Y} (x, y)

E [.]

represents the expectation operator, then consider the following relations:
1.

E [X Y] = E [X] E [Y]

f_{X Y} (x, y) = f_{X} (x) f_{Y} (y)

Which of the above two relations can confirm the statistical independency of

X

Y

?

Q. The probability density function of a random variable 'X' is given as

f_{x} (x)

. A random variabel Y is defined as Y = 2X. The PDF of random variable 'Y' is defined as

k f_{x} (\frac{y}{2})

, then the value of 'k' is equal to

Q. The probability density function (PDF) of a random variable, X is given by,

f_{X} (x) = K e^{- \frac{(x + 1)^{2}}{18}}

The value of K will be______.

X

Y

are two statistically independent random variables. If

X

has uniform PDF in the interval

[0, 2]

Y

has uniform PDF in the interval

[0, 4]

, then the value of

E [X Y]

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Probability

QUANTITATIVE APTITUDE

Watch in App

explore_more_icon

Explore more

Other Quantitative Aptitude

Join BYJU'S Learning Program

CrossIcon