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Question

The probability density plots of 1s and 2s atomic orbitals are given in figures.
The density of dots in a region represents the probability density of finding electrons in the region.
On the basis of the above diagram, which of the following statements is incorrect?
927693_10e3093b89b8405c8834377a836c096a.png

A
1s and 2s orbitals are spherical in shape.
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B
The probability of finding the electron is maximum near the nucleus.
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C
The probability of finding the electron at a given distance is equal in all directions.
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D
The probability density of electrons for 2s orbital decreases uniformly as distance from the nucleus increases.
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Solution

The correct option is D The probability density of electrons for 2s orbital decreases uniformly as distance from the nucleus increases.
s-orbitals are spherically symmetric orbitals. Thus, the probability of finding the electron at a given distance is equal in all directions.

Since the number of angular nodes =l=0 (l=s), the probability of finding an electron is maximum near the nucleus.
And, total number of nodes =nl

For 1s-orbital, the number of nodes = 0. Thus the probability density is maximum at the nucleus and decreases sharply with the distance from the nucleus.

In case of 2s-orbital, number of nodes = 2-1 = 1. Thus it has two maxima separated by a region of a nodal surface. The probability density is maximum near the nucleus and decreases sharply to zero and then start increasing again and after reaching a maxima falls abruptly.

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