You visited us 1 times! Enjoying our articles? Unlock Full Access!

Probability Distribution

The probabili...

Question

The probability distribution of a discrete random variable X is given in the following table :
$X = x$ $0$ $1$ $2$
$P (x)$ $4 C^{3}$ $4 C - 13 C^{2}$ $7 C - 1$
; $C > 0$ then $C =$ ________.

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

and

- \frac{1}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A $2$
B $1$
C $\frac{1}{4}$
Probability distribution is given by
$P (X) = P (X = 0) + P (X = 1) + P (X = 2)$
$= 4 C^{3} + 4 C - 13 C^{2} + 7 C - 1$
Since, total probability is $1$
$∴ 4 C^{3} + 4 C - 13 C^{2} + 7 C - 1 = 1$
$∴ C = 1, 2, \frac{1}{4}$ .

Suggest Corrections

Similar questions

X

\begin{matrix} X = x & 0 & 1 & 2 P (x) & 4 C^{3} & 4 C - 13 C^{2} & 7 C - 1 \end{matrix}

C > 0

C =

X

$X = x$	$1$	$2$	$3$	$4$	$5$
$P (X = x)$	$k$	$2 k$	$3 k$	$4 k$	$5 k$

P (X \leq 4)

X

Y

$X$	$0$	$1$	$2$	3
$P (X)$	$\frac{1}{5}$	$\frac{2}{5}$	$\frac{1}{5}$	$\frac{1}{5}$

$Y$	$0$	$1$	$2$	$3$
$P (Y)$	$\frac{1}{5}$	$\frac{3}{10}$	$\frac{2}{5}$	$\frac{1}{10}$

X

C =

X = x : 1, 2, 3, 4

P (X = x) : C, 2 C, 3 C, 4 C

\frac{1}{2} 1 \frac{3}{2} 2

Join BYJU'S Learning Program