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Question

The probability distribution of a discrete random variable X is given in the following table :

X=x012
P(x)4C34C−13C27C−1
; C>0 then C= ________.

A
2
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B
1
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C
14
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D
1 and 14
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Solution

The correct options are
A 2
B 1
C 14
Probability distribution is given by
P(X)=P(X=0)+P(X=1)+P(X=2)
=4C3+4C13C2+7C1
Since, total probability is 1
4C3+4C13C2+7C1=1
C=1,2,14.

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