Question

The probability distribution of a random variable $X$ is given as follows. The value of $p$ is

$X$	$-5$	$-4$	$-3$	$-2$	$-1$	$0$	$1$	$2$	$3$	$4$	$5$
$p(X=x)$	$p$	$2p$	$3p$	$4p$	$5p$	$7p$	$8p$	$9p$	$10p$	$11p$	$12p$

The value of $p$is

• A. $\frac{1}{72}$
• B. $\frac{3}{73}$
• C. $\frac{5}{72}$
• D. $\frac{1}{74}$
• E. $\frac{1}{73}$

Answer 1

The correct option is A

$\frac{1}{72}$

Explanation for the correct option

We know that sum of all the probabilities is equal to $1.$

Therefore, $p+2p+3p+4p+5p+7p+8p+9p+10p+11p+12p=1$

$$\begin{gathered} \Rightarrow 72p=1 \\ \Rightarrow p=\frac{1}{72} \end{gathered}$$

Hence the correct option is option(A)