The probability distribution of a random variable X is given below- beginarray -c- c-c- c-c- Whe X - x -0818283 31 hline P X - x -lfrac110-frac210-frac310- frac 410 hlinelend array Then the variance of X isA- 4B- 1C- 2D- 3

The correct option is B 1 Mean μ=2 σ^2+μ^2=5 ⇒σ^2=1 ...

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Probability Distribution

The probabili...

Question

The probability distribution of a random variable X is given below:

$\begin{matrix} X = x & 0 & 1 & 2 & 3 P (X - x) & \frac{1}{10} & \frac{2}{10} & \frac{3}{10} & \frac{4}{10} \end{matrix}$

Then the variance of X is

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The probability distribution of a random variable X is given below:

$\begin{matrix} X = x & 0 & 1 & 2 & 3 P (X - x) & \frac{1}{10} & \frac{2}{10} & \frac{3}{10} & \frac{4}{10} \end{matrix}$

Then the variance of X is

X

\begin{matrix} X = x & 0 & 1 & 2 P (x) & 4 C^{3} & 4 C - 13 C^{2} & 7 C - 1 \end{matrix}

C > 0

C =

x

X = x : 0123

p (X = x) : \frac{1}{3} \frac{1}{2} 0 \frac{1}{6}

A random variable X has the following probability distribution.

X	0	1	2	3	4	5	6	7
P (X)	0	k	2k	2k	3k	k²	2k²	7k² + k

Determine

(i) k

(ii) P (X < 3)

(iii) P (X > 6)

(iv) P (0 < X < 3)

x

p (x = k) = \frac{(k + 1) C}{2^{k}}, k = 0, 1, 2, 3, . . . . . . . . . . . .

C .

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