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Probability

The probabili...

Question

The probability distribution of a random variable $X$ is given below, then $K =$
$X = x_{1} : 1, 2, 3, 4$
$p (X = x_{1}) : 2 k, 4 k, 3 k, k$

\frac{1}{4}

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\frac{1}{5}

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\frac{1}{10}

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\frac{1}{15}

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Solution

The correct option is D $\frac{1}{10}$
$4 \sum 1 P (X = x) = 1$
$K (2 + 4 + 3 + 1) = 1$
$K = \frac{1}{10}$

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