The probability for a randomly selected number out of $1, 2, 3, 4, . . . . ., 25$ to be a prime number is:

\frac{2}{25}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{23}{25}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{10}{25}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{9}{25}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{9}{25}$
There are $25$ numbers from $1$ to $25$ out of which
$2, 3, 5, 7, 11, 13, 17, 19, 23,$ i.e $9$ numbers are prime.
So,the probability for a randomly selected number out of $1, 2, 3....25$ to be a prime number is $\frac{9}{25}$

Suggest Corrections

Similar questions

Q. A number is selected from numbers 1 to 25. The probability that it is prime is

(a)

\frac{2}{3}

(b)

\frac{1}{6}

(c)

\frac{1}{3}

(d)

\frac{5}{6}

Q. From

X = {1, 2, \dots 25}

a number is selected randomly from

X

and found to be prime. The probability that it is more than

12

Find the probability that a number selected at random from the numbers 1 to 25 is not a prime number.

Q. What is the probability that a number selected from the number 1, 2, 3,....,25 is a prime the number. When each of the given numbers is equally to be selected?

There are 25 tickets numbered as 1, 2, 3, 4,..., 25 respectively. One ticket is drawn at random. What is the probability that the number on the ticket is a multiple of 3 or 5?
(a) $\frac{2}{5}$ (b) $\frac{11}{25}$ (c) $\frac{12}{25}$ (d) $\frac{13}{25}$

Join BYJU'S Learning Program

The probability for a randomly selected number out of 1,2,3,4,.....,25 to be a prime number is:

The correct option is D 925There are 25 numbers from 1 to 25 out of which 2,3,5,7,11,13,17,19,23, i.e 9 numbers are prime.So,the probability for a randomly selected number out of 1,2,3....25 to be a prime number is 925

The probability for a randomly selected number out of $1, 2, 3, 4, . . . . ., 25$ to be a prime number is:

The correct option is D $\frac{9}{25}$
There are $25$ numbers from $1$ to $25$ out of which
$2, 3, 5, 7, 11, 13, 17, 19, 23,$ i.e $9$ numbers are prime.
So,the probability for a randomly selected number out of $1, 2, 3....25$ to be a prime number is $\frac{9}{25}$