The probability for a randomly selected number out of 101, 102, 103, 104, 105, ..., 120 to be divisible by 3, is

\frac{3}{20}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{9}{20}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{7}{20}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{7}{20}$

Total numbers = 20
Numbers divisible by 3: 102, 105, 108, 111, 114, 117, 120
$∴ Total number of favourable numbers = 7$
$∴ Required Probability = \frac{Number of favourable numbers}{Total number of numbers}$
$= \frac{7}{20}$
Hence, the correct answer is option (d).

Suggest Corrections

Similar questions

Find the number from each of the following expanded forms:

(a) 8 × 10⁴ + 6 × 10³ + 0 × 10² + 4 × 10¹ + 5 × 10⁰

(b) 4 × 10⁵+ 5 × 10³+ 3 × 10²+ 2 × 10⁰

(d) 9 × 10⁵ + 2 × 10² + 3 × 10¹

Write the numeral whose expanded form is given below:
(i) $6 \times 10^{4} + 3 \times 10^{3} + 0 \times 10^{2} + 7 \times 10^{1} + 8 \times 10^{0}$
(ii) $9 \times 10^{6} + 7 \times 10^{5} + 0 \times 10^{4} + 3 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 2 \times 10^{0}$
(iii) $8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 2 \times 10^{2} + 9 \times 10^{1} + 6 \times 10^{0}$

Q. Express the number :

8 \times 10^{5} + 7 \times 10^{4} + 5 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 9 \times 10^{0}

Question 61

$876543 = 8 \times 10^{5} + 7 \times 10^{4} + 6 \times 10^{3} + 5 \times 10^{2} + 4 \times 10^{1} + 3 \times 10^{0}$

Q. A number is randomly selected from the first 40 natural numbers. What is the probability that the selected number is divisible by 5 or 7?

Join BYJU'S Learning Program

The probability for a randomly selected number out of 101, 102, 103, 104, 105, ..., 120 to be divisible by 3, is

The correct option is D 720 Total numbers = 20 Numbers divisible by 3: 102, 105, 108, 111, 114, 117, 120 ∴Total number of favourable numbers=7 ∴Required Probability=Number of favourable numbersTotal number of numbers =720 Hence, the correct answer is option (d).