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Question

The probability for a randomly selected number out of 101, 102, 103, 104, 105, ..., 120 to be divisible by 3, is

A
320
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B
12
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C
920
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D
720
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Solution

The correct option is D 720

Total numbers = 20
Numbers divisible by 3: 102, 105, 108, 111, 114, 117, 120
Total number of favourable numbers=7
Required Probability=Number of favourable numbersTotal number of numbers
=720
Hence, the correct answer is option (d).

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