The probability of a leap year having $5$ Sundays in February is :

0

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1

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\frac{1}{7}

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\frac{2}{7}

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Solution

The correct option is D $\frac{2}{7}$
$\begin{matrix} t h e p r o b a b i l i t y o f a l e a p y e a r h a v i n g 5 s u n d a y s i n F a b r u a r y P (5 s u n d a y s) = \frac{2}{7} ∵ L e a p y e a r = 366 d a y = 52 \times 7 \times 2 \end{matrix}$

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