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Question

The probability of a man hitting a target is 110. The least number of shots required, so that the probability of his hitting the target at least once is greater than 14 is


A

4

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B

3

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C

2

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D

1

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Solution

The correct option is B

3


Explanation of the correct option.

Solve the given expression.

Given expression,

Whenever we aim for a target ,there are two possible event to occur ,

either hitting the target which is denoted by H

or missing the target which is denoted by M

Here, the probability of hitting a target PH=110

and the probability of missing a target PM=910

Now ,we have PH+PM=1

So, 1-probabilityofallshotsresultinfailure>14

1-PMn>141-910n>14910n<34n3

Therefore,least number of shots required so that the probability of his hitting the target at least once is greater than 14 is 3.

Hence option (B) is the correct option.


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