Question

The probability of drawing two red balls in succession from a bag containing $4$ red and $5$ black balls, when the ball that is drawn $1\text{st}$ is not replaced is

• A. $\frac{4}{9}$
• B. $\frac{1}{6}$
• C. $\frac{1}{8}$
• D. $\frac{5}{6}$

Answer 1

The correct option is B $\frac{1}{6}$

The probability of drawing first red ball from a bag $=\frac{4}{9}$
Since when the ball that is drawn $1\text{st}$ is not replaced then the probability of drawing second red ball from a bag $=\frac{3}{8}$
The probability of drawing two red balls in succession from a bag $=\frac{4}{9}\times \frac{3}{8}=\frac{1}{6}$