The probability of finding the electron in $p_{x} -$ orbital is:

maximum on two opposite sides of the nucleus along x-axis

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zero at the nucleus

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same on all the sides around the nucleus

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zero on the z-axis

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Solution

The correct options are
B maximum on two opposite sides of the nucleus along x-axis
C zero at the nucleus
D zero on the z-axis
$p_{x}$ orbital is a dumbbell-shaped orbital along the x-axis. So, the probability of finding the electron in $p_{x}$ orbital is maximum on the x-axis and zero at the nucleus.

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Similar questions

Q. An orbital is the space around the nucleus where the probability of finding electron is .

Q. The probability of finding an electron in the

p_{x}

orbital:

Question 03

The probability density plots of 1s and 2s orbital are given in figure.

The density of dots in region represents the probability density of finding electrons in the region. On the basis of above diagram which of the following statements is incorrect ?

(a) 1s and 2s orbitals are spherical in shape

(b) The probability of finding electron is maximum near the nucleus

(d) The probability density of electrons for 2s orbital decreases uniformly as distance from the nucleus increases

Q. Orbit is a region of space around the nucleus where the probability of finding an electron is maximum.

Q. A line is drawn through

P (3, 4)

inclined to

x -

axis at an angle

3 π / 4

. Find its equation and also the co-ordinates of two points on it on opposite sides of

P

at a distance

\sqrt{2}

from it.

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The probability of finding the electron in px−orbital is:

The correct options are B maximum on two opposite sides of the nucleus along x-axis C zero at the nucleus D zero on the z-axispx orbital is a dumbbell-shaped orbital along the x-axis. So, the probability of finding the electron in px orbital is maximum on the x-axis and zero at the nucleus.

The probability of finding the electron in $p_{x} -$ orbital is: