The probability of getting a composite number in a throw of dice is

1/2

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1/3

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1/6

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Solution

The correct option is C
1/3

The composite numbers among 1, 2, 3, 4, 5 and 6 are 4 and 6. Hence, the number of favourable outcomes is 2 and the total number of outcomes is 6.

Thus, the probability of getting a composite number in a throw of dice = $\frac{n u m b e r o f f a v o u r a b l e o u t c o m e s}{t o t a l n u m b e r o f o u t c o m e s}$ = $\frac{2}{6}$ = $\frac{1}{3}$

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Similar questions

The probability of getting a composite number in a throw of dice is ___.

The probability of getting a composite number in a throw of an unbiased dice is___

4, 5 o r 6

1, 2, 3 o r 4

Question 77

The probability of getting number 6 in a throw of a die is $\frac{1}{6} .$ Similarly, the probability of getting a number 5 is $\frac{1}{5} .$

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