Question

The probability of getting a number between 1 and 100 which is divisible by 1 and itself is

• A. $\frac{1}{4}$
• B. $\frac{1}{2}$
• C. $\frac{25}{98}$
• D. $\frac{1}{3}$

Answer 1

Answer: (C)

$\frac{25}{98}$

which numbers are divisible by 1 and itself are prime number,
So prime numbers between 1 and 100 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.
25 numbers out of 98 number (We have to exclude 1 and 100 also)
Probability for numbers which are divisible by 1 and itself is$=\frac{25}{98}$