Question

The probability of getting a number greater than 2 in throwing a die is -

• A. $\frac{2}{3}$
• B. $\frac{1}{3}$
• C. $\frac{4}{3}$
• D. $\frac{1}{4}$

Answer 1

The correct option is A $\frac{2}{3}$

$3,4,5,6i.e.,$ $4$ $possibilities$ $there$ $out$ $of$ $6$ $and$ $hence$ $probability$ $=\frac{4}{6}=\frac{2}{3}$