The probability of getting an ever number, when a die is thrown once, is:
When a die is thrown once, the sample space is given by, S = {1,2,3,4,5, and 6}
Then, the event, E of getting an ever number is given by, E = {2,4, and 6}
∴ Probability of getting an even number = P (E)
∴P(E)=Number of favourable outcomesNumber of all possible outcomes=36=12
The correct answer is 12 which is given by option A.