The probability of getting different suit cards and different denomination cards when two cards are drawn from a pack is
A
1317
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B
1334
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C
1217
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D
617
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Solution
The correct option is C1217 Let 1st card be any card.........in any case the card left ll be 51 out of that 51 cards 12 cards will be of same suit while 3 cards with same denomination so the left cards are 51−12−3=36 Probability = 36/51=12/17