Question

The probability of getting heads in heads in both trials when a balanced coin is tossed twice will be

• A. $\frac{1}{4}$
• B. $\frac{1}{2}$
• C. $1$
• D. $\frac{3}{4}$

Answer 1

The correct option is A $\frac{1}{4}$

Probability of getting head in one trial = $\frac{1}{2}$
$\therefore$ probability of getting heads in both the trials $=\frac{1}{2}\times \frac{1}{2}=\frac{1}{4}.$