The probability of getting more than 7 when a pair of dice are thrown is

\frac{7}{36}

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\frac{7}{12}

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\frac{5}{12}

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None of these

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Solution

The correct option is D $\frac{5}{12}$
$W h e n p a i r o f d i c e i s r o l l e d t o t a l o u t c o m e s = 6 * 6 = 36 f a v o u r a b l e o u t c o m e f o r g e t t i n g s u m m o r e t h a m 7 a r e l e t 1 a p p e a r s o n a d i c e t h a n i t s n o t p o s s i b l e l e t 2 a p p e a r s o n a d i c e t h a n 6 i s p o s s i b l e l e t 3 a p p e a r s o n a d i c e t h a n 5, 6 i s p o s s i b l e l e t 4 a p p e a r s o n a d i c e t h a n 4, 5, 6 i s p o s s i b l e l e t 5 a p p e a r s o n a d i c e t h a n 3, 45, 6 i s p o s s i b l e l e t 6 a p p e a r s o n a d i c e t h a n 2, 3, 45, 6 i s p o s s i b l e T o t a l f a v o u r a b l e o u t c o m e = 15 p r o b a b i l i t y o f g e t t i n g s u m m o r e t h a m 7 = \frac{15}{36} = \frac{5}{12}$

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