The probability of happening an event A is 0.5 and that of B is 0.3. If A and B are mutually exclusive events, then the probability of happening neither A nor B is
A
0.6
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B
0.2
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C
0.21
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D
None of these
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Solution
The correct option is B 0.2 P(¯¯¯¯A∩¯¯¯¯B)=P(¯¯¯¯A∪¯¯¯¯B)−1−P(A∪B) Since A and B are mutually exclusive, P(A∪B)=P(A)+P(B) Hence required probability =1–(0.5+0.3)=0.2