The probability of happening of an event in an experiment is 0.4. The probability of happening of the event atleast once, if the experiment is repeated 3 times under similar conditions is
A
0.216
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B
0.784
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C
0.64
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D
0.32
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Solution
The correct option is D0.784 p=0.4 q=1−0.4=0.6 Hence the required probability is 3C1(0.4)1(0.6)2+3C2(0.4)2(0.6)1+3C3(0.4)3(0.6)0 =3(0.4)(0.36)+3(0.16(0.6))+(0.064) =0.432+0.288+0.064 =0.784