The probability of obtaining an even prime number on each die, when a pair of dice is rolled is (A) 0 (B) (C) (D)

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Solution

If two dice are rolled, the total number of outcomes is 36.

The only even prime number is 2.

Let, A be the event for getting an even prime number on each dice.

P( A )= 1 6 × 1 6 = 1 36

Hence, the option (D) is correct.

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The probability of obtaining an even prime number on each die, when a pair of dice is rolled is

(A) 0 (B) (C) (D)

Choose the correct answer.
The probability of obtaining an even prime number on each die when a pair of dice is rolled is
(a) zero (b) $\frac{1}{3}$ (c) $\frac{1}{12}$ (d) $\frac{1}{36}$

Q. E is the event of 'getting an even prime number' on rolling a dice once. The probability of it's complementary event is .

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The probability of obtaining an even prime number on each die, when a pair of dice is rolled is (A) 0 (B) (C) (D)

If two dice are rolled, the total number of outcomes is 36. The only even prime number is 2. Let, A be the event for getting an even prime number on each dice. P( A )= 1 6 × 1 6 = 1 36 Hence, the option (D) is correct.

If two dice are rolled, the total number of outcomes is 36.

The only even prime number is 2.

Let, A be the event for getting an even prime number on each dice.

P( A )= 1 6 × 1 6 = 1 36

Hence, the option (D) is correct.