The probability of obtaining at least one head when we toss n unbiased coins is
A
Cn02n
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B
1−Cnr2n
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C
1−12n
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D
Cnr2n
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Solution
The correct option is A1−12n P(at least 1 head) =1− P(all tails) Now P(all tails) = P(tails in 1st toss) × P(tails in 2nd toss) × P(tails in 3rd toss) .... × P(tails in nth toss) =12 x 12 x 12 x .......12 (upto n terms) =12n So, P(at least 1 head) =1−12n