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Question

The probability of obtaining at least one head when we toss n unbiased coins is

A
Cn02n
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B
1Cnr2n
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C
112n
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D
Cnr2n
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Solution

The correct option is A 112n
P(at least 1 head) =1 P(all tails)
Now P(all tails) = P(tails in 1st toss) × P(tails in 2nd toss) × P(tails in 3rd toss) .... × P(tails in nth toss)
=12 x 12 x 12 x .......12 (upto n terms)
=12n
So, P(at least 1 head) =112n

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