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Union of Sets

The probabili...

Question

The probability of occurrence of two events $E$ and $F$ are $0.25$ and $0.30$ respectively The probability of their simultaneous occurrence is $0.14$ . The probability that either $E$ occurs or $F$ occurs is

0.31

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0.41

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0.69

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0.89

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Solution

The correct option is B $0.41$
Given, $P (E) = 0.25, P (F) = 0.30, P (E$ and $F) = 0.14$
Thus, $P (E$ or $F) = P (E) + P (F) - P (E$ and $F)$
$P (E$ or $F) =$ $0.25 + 0.30 - 0.14$
$P (E$ or $F) =$ $0.45$
Thus, probability of occurrence of $E$ or $F =$ $0.41$

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The probability of occurrence of two events E and F are 0.25 and 0.30 respectively The probability of their simultaneous occurrence is 0.14. The probability that either E occurs or F occurs is

The correct option is B 0.41Given, P(E)=0.25,P(F)=0.30,P(E and F)=0.14Thus, P(E or F)=P(E)+P(F)−P(E and F)P(E or F)= 0.25+0.30−0.14P(E or F)= 0.45Thus, probability of occurrence of E or F= 0.41

The probability of occurrence of two events $E$ and $F$ are $0.25$ and $0.30$ respectively The probability of their simultaneous occurrence is $0.14$ . The probability that either $E$ occurs or $F$ occurs is

The correct option is B $0.41$
Given, $P (E) = 0.25, P (F) = 0.30, P (E$ and $F) = 0.14$
Thus, $P (E$ or $F) = P (E) + P (F) - P (E$ and $F)$
$P (E$ or $F) =$ $0.25 + 0.30 - 0.14$
$P (E$ or $F) =$ $0.45$
Thus, probability of occurrence of $E$ or $F =$ $0.41$