The probability of picking a number which ends with $3$ from first $100$ natural numbers is

0.1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.13

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 0.1
Favourable cases $3, 13, 23, . . ., 83, 93$
No .of favourable cases is $10$
No .of possible cases $100$
Probability is $\frac{10}{100} = 0.1$

Suggest Corrections

Similar questions

100

100

x

100

x + \frac{100}{x} > 50

x + \frac{100}{x} > 50

Join BYJU'S Learning Program