The probability of rolling a fair die and getting a number that is greater than 2π is (take π=3.14)
A
P(Number>6.28)=0
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B
P(Number>6.28)=0.5
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C
P(Number>6.28)=1
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Solution
The correct option is AP(Number>6.28)=0 2π=6.28
Since all the numbers on a die are less than or equal to 6, this is an impossible event.
Hence, P(Number>6.28)=0