Question

The probability of students playing basketball and football and both the games is given below:
What is the probability of students playing a game when they have already played football?

• A. $\frac{247}{255}$
• B. $\frac{15}{14}$
• C. $\frac{250}{247}$
• D. $\frac{255}{247}$

Answer 1

The correct option is D $\frac{255}{247}$

$\text{P(Football and basketball both are played)}=\frac{15}{19}$

$\text{P (Football is played)}=\frac{13}{17}$

P(A Game is played when football is already being played)

$=\frac{\text{Football and basketball both are played}}{\text{Football is played}}$

$=\frac{\frac{15}{19}}{\frac{13}{17}}⟹\frac{15}{19}\times \frac{17}{13}⟹\frac{255}{247}$