The probability of throwing 16 added sum appeared on all the dices in one throw with three dice is

\frac{1}{36}

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\frac{1}{18}

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\frac{1}{72}

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\frac{1}{9}

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Solution

The correct option is A $\frac{1}{36}$
$T h r e e d i c e s a r e t h r o w n L e t v a l u e s a p p e a r e d o n d i c e s b e x, y a n d z F o r x + y + z = 16 p o s s i b l e c a s e s a r e 466, 664, 646, 556, 655, 565 T o t a l c a s e s a r e 6 T o t a l n u m b e r o f c a s e s = 6 * 6 * 6 T h e r e f o r e p r o b a b i l i t y = \frac{6}{6 * 6 * 6} = \frac{1}{36}$

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In a single throw a three dice, find the probability of gettin the same number on all the three dice.

4

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