The probability that a bomb will hit a target is $0.8$ . Find the probability that out of $10$ bombs dropped, exactly $2$ will hit the target.

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Solution

Here probability of success is $p = 0.8$ ,
and number of trials $, n = 10$

Hence using bernouli theorem

Probability of getting $r$ success out of $n$ is, $P (X = r) =^{n} C_{r} p^{n - r} (1 - p)^{r}$

Here $n = 10, r = 4$

So required probability $= 10 C_{4} (0.8)^{6} (0.2)^{4} = 0.088$

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The probability that a bomb will hit a target is 0.8. Find the probability that out of 10 bombs dropped, exactly 2 will hit the target.

Here probability of success is p=0.8,and number of trials ,n=10Hence using bernouli theorem Probability of getting r success out of n is, P(X=r)=nCrpn−r(1−p)rHere n=10,r=4So required probability =10C4(0.8)6(0.2)4=0.088

The probability that a bomb will hit a target is $0.8$ . Find the probability that out of $10$ bombs dropped, exactly $2$ will hit the target.

Here probability of success is $p = 0.8$ ,
and number of trials $, n = 10$

Hence using bernouli theorem

Probability of getting $r$ success out of $n$ is, $P (X = r) =^{n} C_{r} p^{n - r} (1 - p)^{r}$

Here $n = 10, r = 4$

So required probability $= 10 C_{4} (0.8)^{6} (0.2)^{4} = 0.088$