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Question

The probability that a bulb produced by a factory will fuse after 100 days of use is 0.05. The probability that out of 5 such bulbs at least one will fuse after 100 days of use is

A
(1920)5
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B
1(1920)551C(1920)4(120)1
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C
1(1920)5
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D
(1920)5+51C(1920)4(120)1
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Solution

The correct option is C 1(1920)5
Probability that bulb will fuse after 100 days =0.5=120
Probability that bulb will not fuse after 100 days =1120=1920
Probability that out of 5 such bulbs at least one will fuse =1 Probability that out of 5 none bulb will fuse
15C0×(120)0×(1920)5=1(1920)5

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