The probability that a bulb selected at random has a minimum battery life of $900$ hours

\frac{11}{40}

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\frac{25}{80}

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\frac{21}{40}

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\frac{29}{80}

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Solution

The correct option is A $\frac{11}{40}$
No. of bulbs having minimum battery life of 900 hours = $12 + 10 = 22$
Probability $P = \frac{22}{80} = \frac{11}{40}$
hence, Option $A$ is correct.

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Similar questions

Q. The probability that a bulb selected at random has battery life 1150 hours.

Q. The probability that a bulb selected at random has battery life greater than

700

hours.

Q. Fill In The Blanks

In Q.No. 5, the probability that a bulb selected at random from the the lot has life less than 900 hours is _________.

$80$ bulbs are selected at random from a lot and their lifetime in hours is recorded as under.

$\begin{matrix} Lifetime (in hours) & 300 & 500 & 700 & 900 & 1100 Frequency & 10 & 12 & 23 & 25 & 10 \end{matrix}$

One bulb is selected at random from the lot. What is the probability that the selected bulb has a life more than $500$ hours?

a) $\frac{27}{40}$

b) $\frac{29}{40}$

c) $\frac{51}{6}$

d) $1$

80 bulbs are selected at random from a lot and their life time ( in hours) is recorded in the form of a frequency table given below:

$\begin{matrix} L i f e t i m e (i n h o u r s) & 300 & 500 & 700 & 900 & 1100 F r e q u e n c y & 10 & 12 & 23 & 25 & 10 \end{matrix}$

One bulb is selected at random from the lot. The probability that its life is 1150 h, is:

A) $\frac{1}{80}$
B) $\frac{7}{16}$
C) 0
D) 1

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The probability that a bulb selected at random has a minimum battery life of 900 hours

The correct option is A 1140No. of bulbs having minimum battery life of 900 hours = 12+10=22Probability P=2280=1140hence, Option A is correct.

The probability that a bulb selected at random has a minimum battery life of $900$ hours

The correct option is A $\frac{11}{40}$
No. of bulbs having minimum battery life of 900 hours = $12 + 10 = 22$
Probability $P = \frac{22}{80} = \frac{11}{40}$
hence, Option $A$ is correct.