The probability that a bulb selected at random has battery life greater than $700$ hours.

\frac{29}{80}

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\frac{1}{4}

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\frac{11}{80}

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\frac{11}{40}

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Solution

The correct option is C $\frac{11}{40}$
No. of bulbs having battery life $1150$ hours $= 0$
Hence probability of selecting this is zero.
No. of bulbs having battery life greater than $700$ hours $= 12 + 10 = 22$
Hence, probability of selecting this $= \frac{22}{80} = \frac{11}{40}$

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Similar questions

Q. The probability that a bulb selected at random has a maximum battery life of 700 hours is

Q. The probability that a bulb selected at random has battery life 1150 hours.

$80$ bulbs are selected at random from a lot and their lifetime in hours is recorded as under.

$\begin{matrix} Lifetime (in hours) & 300 & 500 & 700 & 900 & 1100 Frequency & 10 & 12 & 23 & 25 & 10 \end{matrix}$

One bulb is selected at random from the lot. What is the probability that the selected bulb has a life more than $500$ hours?

a) $\frac{27}{40}$

b) $\frac{29}{40}$

c) $\frac{51}{6}$

d) $1$

Q. Fill In The Blanks

In Q.No. 5, the probability that a bulb selected at random from the the lot has life less than 900 hours is _________.

The following table gives the life time of 400 neon lamps:

$\begin{matrix} Life time (in hours) & 300 - 400 & 400 - 500 & 500 - 600 & 600 - 700 & 700 - 800 & 800 - 900 & 900 - 1000 Number of lamps & 14 & 56 & 60 & 86 & 74 & 62 & 48 \end{matrix}$

A bulb is selected at random. Find the probability that the life time of the selected bulb is:

(i) less than 400 (ii) between 300 to 800 hours (iii) at least 700 hours.

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The probability that a bulb selected at random has battery life greater than 700 hours.

The correct option is C 1140No. of bulbs having battery life 1150 hours =0Hence probability of selecting this is zero.No. of bulbs having battery life greater than 700 hours =12+10=22Hence, probability of selecting this =2280=1140

The probability that a bulb selected at random has battery life greater than $700$ hours.

The correct option is C $\frac{11}{40}$
No. of bulbs having battery life $1150$ hours $= 0$
Hence probability of selecting this is zero.
No. of bulbs having battery life greater than $700$ hours $= 12 + 10 = 22$
Hence, probability of selecting this $= \frac{22}{80} = \frac{11}{40}$