The probability that a bullet fired from a point will miss the target is $\frac{3}{4}$ . Three such bullets are fired one after the other from that very point. What is the probability that the target will be hit atleast once in three attempts?

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Solution

The correct option is C

Probability of the bullet not hitting the target in 3 attempts = $\frac{3}{4}$

Probability that none of the 3 bullets will hit the target:
$(\frac{3}{4})^{3} = \frac{27}{64}$

Probability that the target will hit at least once = $1 - \frac{27}{64}$ = $\frac{37}{64}$

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The probability that a bullet fired from a point will miss the target is 34. Three such bullets are fired one after the other from that very point. What is the probability that the target will be hit atleast once in three attempts?

The correct option is C Probability of the bullet not hitting the target in 3 attempts = 34 Probability that none of the 3 bullets will hit the target: (34)3=2764 Probability that the target will hit at least once = 1−2764 = 3764

The probability that a bullet fired from a point will miss the target is $\frac{3}{4}$ . Three such bullets are fired one after the other from that very point. What is the probability that the target will be hit atleast once in three attempts?

The correct option is C

Probability of the bullet not hitting the target in 3 attempts = $\frac{3}{4}$

Probability that none of the 3 bullets will hit the target:
$(\frac{3}{4})^{3} = \frac{27}{64}$

Probability that the target will hit at least once = $1 - \frac{27}{64}$ = $\frac{37}{64}$