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Question

The probability that a couple will have first 3 daughters then 1 son is


A
14
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B
18
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C
34
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D
116
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Solution

The correct option is D 116
Probability of 1st child being daughter = 12
2nd child being daughter = 12
3rd child being daughter = 12
4th child being son = 12

Probability of having 3 daughter and then 1 son
12×12×12×12
=116

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