The probability that A hits a target is 1/4 and the probability that B hits the target is 1/3. If each of them fired once, what is the probability that the target will be hit atleast once.

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Solution

Probability that A hits a target is 1/4
Probability that B hits the target is 1/3
If each of them fired once, probability that the target will be hit atleast once=
1-probability that neither A nor B hits the target
=1-3/4*2/3=1/2

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The probability that A hits a target is 1/4 and the probability that B hits the target is 1/3. If each of them fired once, what is the probability that the target will be hit atleast once.

Probability that A hits a target is 1/4Probability that B hits the target is 1/3If each of them fired once, probability that the target will be hit atleast once=1-probability that neither A nor B hits the target=1-3/4*2/3=1/2

Probability that A hits a target is 1/4
Probability that B hits the target is 1/3
If each of them fired once, probability that the target will be hit atleast once=
1-probability that neither A nor B hits the target
=1-3/4*2/3=1/2