Question

The probability that a leap year selected at random contains $53$ Sunday is -

• A. $\frac{7}{266}$
• B. $\frac{26}{183}$
• C. $\frac{1}{7}$
• D. $\frac{2}{7}$

Answer 1

The correct option is D $\frac{2}{7}$

The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.

So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is$\frac{2}{7}$.