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Question
The probability that a leap year will have 53 Sundays is ______.
The probability that a leap year will have 53 Sundays is ______.
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Solution
The correct option is C 2/7
A leap year has 365 days where 2 days are left out after considering 52 of each day. Therefore these 2 days can be ( Monday, Tuesday) , ( Tuesday, Wednesday) , ( Wednesday, Thursday) , ( Thursday, Friday ), (Friday, Saturday), (Saturday, Sunday) and ( Sunday, Monday). The sample space is 7 Let the required event be E ( getting a Sunday)
n(E) = 2
Therefore, P( getting a Sunday) = n(E)/S
= 2/7
A leap year has 365 days where 2 days are left out after considering 52 of each day. Therefore these 2 days can be ( Monday, Tuesday) , ( Tuesday, Wednesday) , ( Wednesday, Thursday) , ( Thursday, Friday ), (Friday, Saturday), (Saturday, Sunday) and ( Sunday, Monday).
The sample space is 7
Let the required event be E ( getting a Sunday)
n(E) = 2
Therefore, P( getting a Sunday) = n(E)/S
= 2/7
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