Question

The probability that a non leap year selected at random will have $53$ Sundays is

• A. $0$
• B. $\frac{1}{7}$
• C. $\frac{2}{7}$
• D. $\frac{3}{7}$

Answer 1

The correct option is B $\frac{1}{7}$

A non leap year ($365$ days) has $52$ weeks and $1$ day.
It means that there are $52$ sundays for sure in a non leap year.
The probability of that the remaining one day to be Sunday is $\frac{1}{7}$