The probability that a part manufactured by a company will be defective is 0.05. If 15 such parts are selected randomly and inspected, then the probability that at least two parts will be defective is (round off to two decimal places).

0.17

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Solution

The correct option is A 0.17
$(P)_{d e f e c t i v e} = 0.05$
$(P)_{n o n - d e f e c t i v e} = 1 - 0.05 = 0.95$
Probability that atleast two parts will be defective.

$P = [\begin{matrix} ^{15} C_{0} . (0.05)^{0} . (0.95)^{15} + i^{15} C_{1} (0.05) . (0.95)^{14} \end{matrix}] = 0.829$

Required probability

$= 1 - 0.829$
$[P = 0.1709] \approx 0.17$

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The probability that a part manufactured by a company will be defective is 0.05. If 15 such parts are selected randomly and inspected, then the probability that at least two parts will be defective is (round off to two decimal places). 0.17

The correct option is A 0.17(P)defective=0.05 (P)non−defective=1−0.05=0.95 Probability that atleast two parts will be defective. P=[15C0.(0.05)0.(0.95)15 + i15C1(0.05).(0.95)14]=0.829 Required probability =1−0.829 [P=0.1709]≈0.17

The probability that a part manufactured by a company will be defective is 0.05. If 15 such parts are selected randomly and inspected, then the probability that at least two parts will be defective is (round off to two decimal places).

0.17