The probability that a randomly chosen number from a set of 100 natural numbers is divisible by 4 or 6 is

\frac{41}{100}

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\frac{33}{100}

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\frac{37}{100}

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\frac{3}{100}

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Solution

The correct option is B $\frac{33}{100}$
$P (4 o r 6) = P (4) + P (6) - P (4$ and $6)$
$= 25 / 100 + 16 / 100 - 8 / 100 = 33 / 100$

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