The probability that a teacher will give an unannounced test during any class meeting is 1-5-If a student is absent twice- the probability that he will miss atleast one test- is

Probability of( student never misses a test when he is absent) =(1 1/5 )×(1 1/5 ) =16/25 Hence, probability that he will miss atleast one test =1 16/25 =16/2 ...

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Standard XIII

Mathematics

Independent Events

The probabili...

Question

The probability that a teacher will give an unannounced test during any class meeting is $\frac{1}{5}$ .If a student is absent twice, the probability that he will miss atleast one test, is

\frac{7}{25}

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\frac{9}{25}

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\frac{16}{25}

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\frac{24}{25}

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Solution

The correct option is B $\frac{9}{25}$
Probability of( student never misses a test when he is absent)
$= (1 - \frac{1}{5}) \times (1 - \frac{1}{5}) = \frac{16}{25}$
Hence, probability that he will miss atleast one test
$= 1 - \frac{16}{25} = \frac{16}{25}$

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The probability that a teacher will give an unannounced test during any class meeting is 15.If a student is absent twice, the probability that he will miss atleast one test, is

The correct option is B 925Probability of( student never misses a test when he is absent) =(1−15)×(1−15)=1625 Hence, probability that he will miss atleast one test =1−1625=1625

The probability that a teacher will give an unannounced test during any class meeting is $\frac{1}{5}$ .If a student is absent twice, the probability that he will miss atleast one test, is

The correct option is B $\frac{9}{25}$
Probability of( student never misses a test when he is absent)
$= (1 - \frac{1}{5}) \times (1 - \frac{1}{5}) = \frac{16}{25}$
Hence, probability that he will miss atleast one test
$= 1 - \frac{16}{25} = \frac{16}{25}$