Question

The probability that a year chosen at random has $53$ Sunday is given by

• A. $\frac{1}{7}$
• B. $\frac{2}{7}$
• C. $\frac{3}{7}$
• D. $\frac{5}{28}$

Answer 1

The correct option is B $\frac{2}{7}$

A normal year has 52 Sundays, 52 Mondays, 52 Tuesday, 52 Wednesday, 52 Thursday, 52 Fridays,

52 Saturdays, +1 day that could be anything depending upon the year consideration.

For a leap year to have 35 Sundays, it should start from Saturday or Sunday.

So, basically we have to find the probability that year start from Saturday or Sunday (P)

$P=\frac{firstdaytobeSaturdayorSunday}{Totalno.ofdaysinaweek}$

$=\frac{2}{7}$