The probability that an electronic device produced by a company does not function properly is equal to 0.1. If 10 devices are bought, then the probability, to the nearest thousand, that 7 devices function properly is
A
2.057
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B
4.047
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C
1.057
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D
0.057
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Solution
The correct option is D0.057
This problem can be result using a Binomial distribution, in which we have
n identical events with a probability p of success.
The probability that x of the n events get success is given by:
P(x)=nCx×px×(1−p)n−x
Where, nCx can be calculate as:
In this case there a 10 device with a probability 0.9 of function properly and we need to find the probability that 7 of these device function properly, so replacing values, we get:
P(7)=10C7×0.97×(1−0.9)10−7
P(7)=120×0.478×0.001
P(7)=0.057
Finally the probability, to the nearest thousandth, that 7 of the 10 devices function properly is 0.057.